FInd all of the nonunit, nonassociate, and nonconjugate common divisors of and in .
Note that . Since 3 is irreducible and does not divide , we have . Note that , and that these factors are irreducible since their norms are prime. Now , and these factors are also irreducible. Thus the greatest common divisor of and is . Since this element is irreducible, it is (up to associates) the only nontrivial common divisor of and .